题目已知实数xxx满足(x2−2x+1)2+2(x2−2x+1)−3=0(x^{2}-2x+1)^{2}+2(x^{2}-2x+1)-3=0(x2−2x+1)2+2(x2−2x+1)−3=0,那么x2−2x+1x^{2}-2x+1x2−2x+1的值为（ ）A.−1-1−1或333B.−3-3−3或111C.333D.111知识点：解一元二次方程——换元法章节：方程与不等式 / 一元二次方程
