题目如图,ABABAB是⊙O\odot O⊙O的直径,点CCC,DDD在圆上,且ODODOD经过ACACAC中点EEE,连接DCDCDC并延长,与ABABAB的延长线相交于点PPP,若∠CAB=16∘\angle CAB=16^{\circ}∠CAB=16∘,则∠BPC\angle BPC∠BPC的度数为( )A.16∘16^{\circ}16∘B.21∘21^{\circ}21∘C.32∘32^{\circ}32∘D.37∘37^{\circ}37∘知识点:切线的性质章节:图形的性质 / 圆