题目解方程:①−2x2−4x=42-\sqrt{2}x^2-4x=4\sqrt{2}−2x2−4x=42；②(x−1)2+2x(x−1)=0\left(x-1\right)^{2}+2x\left(x-1\right)=0(x−1)2+2x(x−1)=0.知识点：解分式方程章节：方程与不等式 / 分式方程
