题目如图,从⊙O\odot O⊙O外一点PPP引圆的两条切线PAPAPA,PBPBPB,切点分别是AAA,BBB,若∠APB=60∘\angle APB=60^{\circ}∠APB=60∘,PA=5PA=5PA=5,则弦ABABAB的长是( )A.52\frac{5}{2}25B.523\frac{5}{2}\sqrt{3}253C.555D.535\sqrt{3}53知识点:切线长定理章节:图形的性质 / 圆