题目如图,平行四边形ABCDABCDABCD中,AB=6AB=6AB=6,AD=9AD=9AD=9,BEBEBE平分∠ABC\angle ABC∠ABC,交ADADAD于EEE,CF⊥BECF\bot BECF⊥BE交BEBEBE于点NNN,交ADADAD于点FFF,作MNMNMN∥CDCDCD交ADADAD于点MMM,则MN=( )MN=\left(\ \ \right)MN=( )A.12\frac{1}{2}21B.23\frac{2}{3}32C.111D.32\frac{3}{2}23知识点：切线长定理章节：图形的性质 / 圆
如图,平行四边形中,,,平分,交于,交于点,交于点,作∥交于点,则如图,平行四边形中,,,平分,交于,交于点,交于点,作∥交于点,则如图,平行四边形中,,,平分,交于,交于点,交于点,作∥交于点,则