题目已知一次函数y1=kx+m(k≠0)y_{1}=kx+m\left(k\neq 0\right)y1=kx+m(k=0)和二次函数y2=ax2+bx+c(a≠0)y_{2}=ax^{2}+bx+c\left(a\neq 0\right)y2=ax2+bx+c(a=0)部分自变量与对应的函数值如下表xxx…\ldots…−1-1−1000222444555…\ldots…y1y_{1}y1…\ldots…000111333555666…\ldots…y2y_{2}y2…\ldots…000−1-1−1000555999…\ldots…当y2>y1y_{2} \gt y_{1}y2>y1时,自变量xxx的取值范围是( )A.−1<x<2-1 \lt x \lt 2−1<x<2B.4<x<54 \lt x \lt 54<x<5C.x<−1x \lt -1x<−1或x>5x \gt 5x>5D.x<−1x \lt -1x<−1或x>4x \gt 4x>4知识点:一次函数与一元一次不等式章节:函数 / 一次函数