题目如图,AB,AB,AB∥CDCDCD∥EFEFEF,AFAFAF与BEBEBE交于点GGG,若AG=2AG=2AG=2,DG=1DG=1DG=1,DF=5DF=5DF=5,则BCCE\frac{{BC}}{{CE}}CEBC的值为( )A.25\frac{2}{5}52B.35\frac{3}{5}53C.23\frac{2}{3}32D.111知识点:平行线分线段成比例章节:图形的变化 / 图形的相似