题目利用多项式相乘的知识我们易得公式(ax+b)(cx+d)=acx2+(bc+ad)x+bd\left(ax+b\right)\left(cx+d\right)=acx^{2}+\left(bc+ad\right)x+bd(ax+b)(cx+d)=acx2+(bc+ad)x+bd,我们直接套用公式可求得(3x−2)(5x+3)=15x2+(−10+9)x−6=15x2−x−6\left(3x-2\right)\left(5x+3\right)=15x^{2}+\left(-10+9\right)x-6=15x^{2}-x-6(3x−2)(5x+3)=15x2+(−10+9)x−6=15x2−x−6,我们可以逆向运用这个公式,如果2x2−13x+6=(x−6)( )2x^{2}-13x+6=\left(x-6\right)\left(\ \ \right)2x2−13x+6=(x−6)( ),那么括号里应该填( )A.x+1x+1x+1B.2x−12x-12x−1C.2x+12x+12x+1D.x−1x-1x−1知识点:分组分解法章节:数与式 / 因式分解