题目如图,AAA,BBB是⊙O\odot O⊙O上的点,PPP为⊙O\odot O⊙O外一点,连结PAPAPA,PBPBPB,分别交⊙O\odot O⊙O于点CCC,DDD,且AC^=BD^\widehat {AC}=\widehat {BD}AC=BD.(1)(1)(1)求证:PA=PBPA=PBPA=PB;(2)(2)(2)若⊙O\odot O⊙O的半径为666,∠P=60∘\angle P=60^{\circ}∠P=60∘,CD^=3AC^\widehat {CD}=3\widehat {AC}CD=3AC,求图中阴影部分的面积.知识点:切线长定理章节:图形的性质 / 圆