题目如图,△ABC\triangle ABC△ABC中,∠A=40∘\angle A=40^{\circ}∠A=40∘,∠B=72∘\angle B=72^{\circ}∠B=72∘,CECECE平分∠ACB\angle ACB∠ACB,CD⊥ABCD\bot ABCD⊥AB于DDD,DF⊥CEDF\bot CEDF⊥CE,则∠CDF=\angle CDF=∠CDF=____度.知识点：垂线章节：图形的性质 / 相交线与平行线
如图,中,,,平分,于,,则____度.如图,中,,,平分,于,,则____度.如图,中,,,平分,于,,则____度.