题目已知x2−2x=1x^{2}-2x=1x2−2x=1,求代数式(x−1)2+(x−3)(x+3)−2(x−5)\left(x-1\right)^{2}+\left(x-3\right)\left(x+3\right)-2\left(x-5\right)(x−1)2+(x−3)(x+3)−2(x−5)的值.知识点：去括号与添括号章节：数与式 / 代数式
