题目一元二次方程x2−3x=0x^{2}-3x=0x2−3x=0的解是（ ）A.x=3x=3x=3B.x=0x=0x=0C.x1=3x_{1}=3x1=3，x2=0x_{2}=0x2=0D.x1=−3x_{1}=-3x1=−3，x2=0x_{2}=0x2=0知识点：十字相乘法章节：数与式 / 因式分解
