题目如图,在△ABC\triangle ABC△ABC和△BDE\triangle BDE△BDE中,点CCC在边BDBDBD上,边ACACAC交边BEBEBE于点FFF.若AC=BDAC=BDAC=BD,AB=EDAB=EDAB=ED,BC=BEBC=BEBC=BE,则∠ACB\angle ACB∠ACB等于( )A.∠EDB\angle EDB∠EDBB.∠BED\angle BED∠BEDC.2∠ABF2\angle ABF2∠ABFD.12∠AFB\frac{1}{2}\angle AFB21∠AFB知识点:全等三角形的判定章节:图形的性质 / 三角形