题目如图,OA=OBOA=OBOA=OB,ABABAB交⊙O\odot O⊙O于点CCC、DDD,OEOEOE是半径,且OE⊥ABOE\bot ABOE⊥AB于点FFF.(1)(1)(1)求证:AC=BDAC=BDAC=BD；(2)(2)(2)若CD=63CD=6\sqrt{3}CD=63,EF=3EF=3EF=3,求⊙O\odot O⊙O的半径.知识点：垂径定理章节：图形的性质 / 圆
如图,,交于点、,是半径,且于点.如图,,交于点、,是半径,且于点.如图,,交于点、,是半径,且于点.