题目如图,已知ABABAB∥CDCDCD∥EF,EF,EF,那么下列结论正确的是( )A.BCCE=DFAD\frac{BC}{CE}=\frac{DF}{AD}CEBC=ADDFB.ADDF=BCCE\frac{AD}{DF}=\frac{BC}{CE}DFAD=CEBCC.CDEF=BCBE\frac{CD}{EF}=\frac{BC}{BE}EFCD=BEBCD.CDEF=ADAF\frac{CD}{EF}=\frac{AD}{AF}EFCD=AFAD知识点:平行线分线段成比例章节:图形的变化 / 图形的相似