题目二元一次方程组{x−y=1x+y=5\left\{{\begin{array}{l}{x-y=1}\\{x+y=5}\end{array}}\right.{x−y=1x+y=5的解是（ ）A.{x=2y=1\left\{{\begin{array}{l}{x=2}\\{y=1}\end{array}}\right.{x=2y=1B.{x=2y=3\left\{{\begin{array}{l}{x=2}\\{y=3}\end{array}}\right.{x=2y=3C.{x=3y=2\left\{{\begin{array}{l}{x=3}\\{y=2}\end{array}}\right.{x=3y=2D.{x=4y=1\left\{{\begin{array}{l}{x=4}\\{y=1}\end{array}}\right.{x=4y=1知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
