题目已知反比例函数y=1−2mxy=\frac{1-2m}{x}y=x1−2m的图象上有两点A(x1A(x_{1}A(x1,y1)y_{1})y1)、B(x2B(x_{2}B(x2,y2)y_{2})y2),当x1<0<x2x_{1} \lt 0 \lt x_{2}x1<0<x2时,有y1<y2y_{1} \lt y_{2}y1<y2,则mmm的取值范围是____.知识点：不等式的解集章节：方程与不等式 / 不等式与不等式组
