题目关于xxx的方程xx−1−1=a+2x(x+2)(x−1)\dfrac{x}{x-1}-1=\dfrac{a+2x}{(x+2)(x-1)}x−1x−1=(x+2)(x−1)a+2x有增根，那么aaa的值为()(\quad)()A.111B.−4-4−4C.−1-1−1或−4-4−4D.111或444知识点：分式方程的增根章节：方程与不等式 / 分式方程
