题目如图,AB,AB,AB∥CDCDCD∥EF,AFEF,AFEF,AF与BEBEBE相交于点GGG,且AG=2AG=2AG=2,GD=1GD=1GD=1,DF=5DF=5DF=5,则CE:BC=( )CE:BC=\left(\ \ \right)CE:BC=( )A.5:35:35:3B.1:31:31:3C.3:53:53:5D.2:32:32:3知识点:平行线分线段成比例章节:图形的变化 / 图形的相似