题目如图,在Rt△ABCRt\triangle ABCRt△ABC中,∠ACB=90∘\angle ACB=90^{\circ}∠ACB=90∘,AB=6AB=6AB=6,点DDD,EEE分别在边ABABAB,ACACAC上,且AD=2DBAD=2DBAD=2DB,AC=2AEAC=2AEAC=2AE,连接BEBEBE,CDCDCD,相交于点OOO,则△ABO\triangle ABO△ABO面积最大值为( )A.94\frac{9}{4}49B.83\frac{8}{3}38C.333D.52\frac{5}{2}25知识点:平行线分线段成比例章节:图形的变化 / 图形的相似