题目若一次函数y=−2x+8y=-2x+8y=−2x+8的图象经过点A(x1A(x_{1}A(x1,y1)y_{1})y1)和点B(x1+2B(x_{1}+2B(x1+2,y2)y_{2})y2),则y1y_{1}y1与y2y_{2}y2的大小关系是（ ）A.y1<y2y_{1} \lt y_{2}y1<y2B.y1=y2y_{1}=y_{2}y1=y2C.y1>y2y_{1} \gt y_{2}y1>y2D.y1⩽y2y_{1}\leqslant y_{2}y1⩽y2知识点：一次函数的性质章节：函数 / 一次函数
