题目先化简,再求值:(x−1x−x−2x+1)÷2x2−xx2+2x+1({\frac{{x-1}}{x}-\frac{{x-2}}{{x+1}}})÷\frac{{2{x^2}-x}}{{{x^2}+2x+1}}(xx−1−x+1x−2)÷x2+2x+12x2−x,其中xxx满足x2−2x−2=0x^{2}-2x-2=0x2−2x−2=0.知识点：分式的化简求值章节：数与式 / 分式
