题目如图,在△ABC\triangle ABC△ABC中,AB=ACAB=ACAB=AC,EB=AFEB=AFEB=AF,直线EFEFEF经过点AAA,BE⊥EFBE\bot EFBE⊥EF于点EEE,CF⊥EFCF\bot EFCF⊥EF于点FFF.求证:AB⊥ACAB\bot ACAB⊥AC.知识点:矩形的判定章节:图形的性质 / 四边形