题目如图,PAPAPA,PBPBPB分别与⊙O\odot O⊙O相切于AAA,BBB两点,DEDEDE与⊙O\odot O⊙O相切于点CCC,与PAPAPA,PBPBPB相交于DDD,EEE两点,若PA=9PA=9PA=9,∠APB=50∘\angle APB=50^{\circ}∠APB=50∘,则△PDE\triangle PDE△PDE的周长和∠ACB\angle ACB∠ACB的度数分别为( )A.999,130∘130^{\circ}130∘B.181818,130∘130^{\circ}130∘C.999,115∘115^{\circ}115∘D.181818,115∘115^{\circ}115∘知识点:切线长定理章节:图形的性质 / 圆