题目在下列方程中，无实数根的方程有()(\quad)()①x−2+4=0\sqrt{x-2}+4=0x−2+4=0：②x−4+3−x=0\sqrt{x-4}+\sqrt{3-x}=0x−4+3−x=0③x+1=−x\sqrt{x+1}=-xx+1=−x④2x−3+3−2x=0\sqrt{2x-3}+\sqrt{3-2x}=02x−3+3−2x=0⑤x2−2x+4=0x^{2}-2x+4=0x2−2x+4=0⑥1x+1+3x−1=6x2−1\dfrac{1}{x+1}+\dfrac{3}{x-1}=\dfrac{6}{x^{2}-1}x+11+x−13=x2−16A.222B.333C.444D.555知识点：分式方程的解章节：方程与不等式 / 分式方程
