题目已知点A(x1A(x_{1}A(x1,y1)y_{1})y1)、B(x2B(x_{2}B(x2,y2)y_{2})y2)在函数y=−2x+by=-2x+by=−2x+b的图象上,且x1<0<x2x_{1} \lt 0 \lt x_{2}x1<0<x2,则下列结论一定成立的是（ ）A.y1+y2<0y_{1}+y_{2} \lt 0y1+y2<0B.y1+y2>0y_{1}+y_{2} \gt 0y1+y2>0C.y1<y2y_{1} \lt y_{2}y1<y2D.y1>y2y_{1} \gt y_{2}y1>y2知识点：正比例函数的图象章节：函数 / 一次函数
