题目如图所示,已知⊙O\odot O⊙O的半径等于444,PPP为⊙O\odot O⊙O外一点,PAPAPA为⊙O\odot O⊙O的切线,PA=2.5PA=2.5PA=2.5,直线POPOPO与⊙O\odot O⊙O相交于CCC,DDD两点,则PCPCPC的长为______.知识点:切线长定理章节:图形的性质 / 圆