题目下列方程有实数根的是（ ）A.3x2+2x+1=03x^{2}+2x+1=03x2+2x+1=0B.x2−x−3=0x^{2}-x-3=0x2−x−3=0C.x2−2x+2=0x^{2}-2x+2=0x2−2x+2=0D.x2−3x+1=0{x}^{2}-\sqrt{3}x+1=0x2−3x+1=0知识点：解分式方程章节：方程与不等式 / 分式方程
