题目(1)(1)(1)计算:∣1−23∣+(−12)−1−(2023−π)0−12|1-2\sqrt{3}|+(-\frac{1}{2})^{-1}-(2023-π)^0-\sqrt{12}∣1−23∣+(−21)−1−(2023−π)0−12；(2)(2)(2)先化简,再求值:(2x+1x+1+x−1)÷x+2x2+2x+1(\frac{2x+1}{x+1}+x-1)÷\frac{x+2}{x^2+2x+1}(x+12x+1+x−1)÷x2+2x+1x+2,其中xxx满足x2−x−2=0x^{2}-x-2=0x2−x−2=0.知识点：分式的化简求值章节：数与式 / 分式
