题目先化简,再求值x2−8x+16x2+2x÷(12x+2−x+2)+1x+4\frac{x^2-8x+16}{x^2+2x}÷(\frac{12}{x+2}-x+2)+\frac{1}{x+4}x2+2xx2−8x+16÷(x+212−x+2)+x+41,其中xxx与111、444构成△ABC\triangle ABC△ABC的三边长,且xxx为整数.知识点：分式的化简求值章节：数与式 / 分式
