题目已知a=2+1a=\sqrt{2}+1a=2+1,b=2−1b=\sqrt{2}-1b=2−1,则a2+b2+3ab=______.a^{2}+b^{2}+3ab=\_\_\_\_\_\_.a2+b2+3ab=______.知识点：二次根式的性质与化简章节：数与式 / 二次根式
