题目(1)(1)(1)解方程组：{x3+y2=24(x−y)=3x−4\begin{cases}\dfrac{x}{3}+\dfrac{y}{2}=2\\ 4(x-y)=3x-4\end{cases}{3x+2y=24(x−y)=3x−4；(2)(2)(2)解不等式组{5x+2>3(x−1)①1−x−62⩾x+23②\begin{cases}5x+2>3(x-1)①\\ 1-\dfrac{x-6}{2}\geqslant\dfrac{x+2}{3}②\end{cases}⎩⎨⎧5x+2>3(x−1)①1−2x−6⩾3x+2②，并写出不等式组的所有非负整数解．知识点：一元一次不等式组的整数解章节：方程与不等式 / 不等式与不等式组
