题目下列方程中，有实数解的是()(\quad)()A.x+2+1=0\sqrt{x+2}+1=0x+2+1=0B.xx2−1=1x2−1\dfrac{x}{x^{2}-1}=\dfrac{1}{x^{2}-1}x2−1x=x2−11C.x−1+1−x=1\sqrt{x-1}+\sqrt{1-x}=1x−1+1−x=1D.x2−3=2\sqrt{x^{2}-3}=2x2−3=2知识点：分式方程的解章节：方程与不等式 / 分式方程
