题目已知二次函数y=0.5x2−x−0.5y=0.5x^{2}-x-0.5y=0.5x2−x−0.5,求顶点坐标.小明的计算过程如下:解:y=0.5x2−x−0.5y=0.5x^{2}-x-0.5y=0.5x2−x−0.5y=0.5(x2−2x)−0.5……y=0.5(x^{2}-2x)-0.5\ldots \ldotsy=0.5(x2−2x)−0.5……①y=0.5(x2−2x+1−1)−0.5……y=0.5(x^{2}-2x+1-1)-0.5\ldots \ldotsy=0.5(x2−2x+1−1)−0.5……②y=0.5(x−1)2−1.5……y=0.5\left(x-1\right)^{2}-1.5\ldots \ldotsy=0.5(x−1)2−1.5……③∴\therefore∴顶点坐标是(1,−1.5)……\left(1,-1.5\right)\ldots \ldots(1,−1.5)……④请你认真检查一下,小明是从第( )步开始出现错误的.A.①B.②C.③D.④知识点:解二元一次方程组——加减消元法章节:方程与不等式 / 二元一次方程组