题目在△ABC\triangle ABC△ABC中,BC=aBC=aBC=a,AB=cAB=cAB=c,AC=bAC=bAC=b,则下列不能作为判定△ABC\triangle ABC△ABC是直角三角形的条件是（ ）A.∠B=∠A+∠C\angle B=\angle A+\angle C∠B=∠A+∠CB.a2−b2=c2a^{2}-b^{2}=c^{2}a2−b2=c2C.a:b:c=3:4:5a:b:c=3:4:5a:b:c=3:4:5D.a:b:c=1:2:3a:b:c=1:2:3a:b:c=1:2:3知识点：勾股定理的逆定理章节：图形的性质 / 三角形
