题目某营养师用甲、乙两种原料配置营养品.每克甲原料含0.50.50.5单位蛋白质和111单位铁质,每克乙原料含0.70.70.7单位蛋白质和0.40.40.4单位铁质.如果每份营养品需要353535单位蛋白质和404040单位铁质,那么每份营养品中甲、乙原料各多少克恰好满足需求?设每份营养品需要甲原料xxx克,乙原料yyy克,则可列方程组( )A.{0.5x+y=350.7x+0.4y=40\left\{\begin{array}{l}0.5x+y=35\\ 0.7x+0.4y=40\end{array}\right.{0.5x+y=350.7x+0.4y=40B.{0.5x+0.7y=35x+0.4y=40\left\{\begin{array}{l}0.5x+0.7y=35\\ x+0.4y=40\end{array}\right.{0.5x+0.7y=35x+0.4y=40C.{x+0.4y=350.5x+0.7y=40\left\{\begin{array}{l}x+0.4y=35\\ 0.5x+0.7y=40\end{array}\right.{x+0.4y=350.5x+0.7y=40D.{0.7x+0.4y=350.5x+y=40\left\{\begin{array}{l}0.7x+0.4y=35\\ 0.5x+y=40\end{array}\right.{0.7x+0.4y=350.5x+y=40知识点:二元一次方程组的应用章节:方程与不等式 / 二元一次方程组