题目如图,点EEE在CDCDCD上,BCBCBC与AEAEAE交于点FFF,AB=CBAB=CBAB=CB,BE=BDBE=BDBE=BD,AE=CDAE=CDAE=CD.求证:∠1=∠2\angle 1=\angle 2∠1=∠2.知识点:垂径定理章节:图形的性质 / 圆