题目如图,PAPAPA,PBPBPB分别与⊙O\odot O⊙O相切于点AAA,BBB、过圆上点CCC作⊙O\odot O⊙O的切线EFEFEF分别交PAPAPA,PBPBPB于点EEE,FFF,若PA=6PA=6PA=6,则△PEF\triangle PEF△PEF的周长是( )A.444B.888C.101010D.121212知识点:切线长定理章节:图形的性质 / 圆