题目已知,x=3+2x=\sqrt{3}+\sqrt{2}x=3+2,y=3−2y=\sqrt{3}-\sqrt{2}y=3−2.求:(1)x+y(1)x+y(1)x+y和xyxyxy的值；(2)(2)(2)求x2−xy+y2x^{2}-xy+y^{2}x2−xy+y2的值.知识点：二次根式的性质与化简章节：数与式 / 二次根式
