题目如图,直线l1/ /l2l_{1}/\!/l_{2}l1//l2,⊙O⊙O⊙O与l1l_{1}l1和l2l_{2}l2分别相切于点AAA和点B.B.B.点MMM和点NNN分别是l1l_{1}l1和l2l_{2}l2上的动点,MNMNMN沿l1l_{1}l1和l2l_{2}l2平移.⊙O⊙O⊙O的半径为111,∠1=60°.∠1=60°.∠1=60°.下列结论错误的是()(\quad)()A.MN=433MN=\dfrac{4\sqrt{3}}{3}MN=343B.l1l_{1}l1和l2l_{2}l2的距离为222C.若∠MON=90°∠MON=90°∠MON=90°,则MNMNMN与⊙O⊙O⊙O相切D.若MNMNMN与⊙O⊙O⊙O相切,则AM=3AM=\sqrt{3}AM=3知识点:切线的判定与性质章节:图形的性质 / 圆