题目向阳村购买玫瑰和芍药两种幼苗种植在景观大道两侧,已知购买222株玫瑰幼苗和333株芍药幼苗共需282828元,购买555株玫瑰幼苗和666株芍药幼苗共需616161元,若设每株玫瑰幼苗xxx元,每株芍药幼苗yyy元,则所列方程组正确的是（ ）A.{3x+2y=286x+5y=61\left\{\begin{array}{l}{3x+2y=28}\\{6x+5y=61}\end{array}\right.{3x+2y=286x+5y=61B.{2x+3y=285x+6y=61\left\{\begin{array}{l}{2x+3y=28}\\{5x+6y=61}\end{array}\right.{2x+3y=285x+6y=61C.{x3+y2=28x6+y5=61\left\{\begin{array}{l}{\frac{x}{3}+\frac{y}{2}=28}\\{\frac{x}{6}+\frac{y}{5}=61}\end{array}\right.{3x+2y=286x+5y=61D.{x2+y3=28x5+y6=61\left\{\begin{array}{l}{\frac{x}{2}+\frac{y}{3}=28}\\{\frac{x}{5}+\frac{y}{6}=61}\end{array}\right.{2x+3y=285x+6y=61知识点：根据实际问题列一次函数关系式章节：函数 / 一次函数
