题目如图,l1l_{1}l1∥l2l_{2}l2,AB=4AB=4AB=4,S△DAB=6S_{\triangle DAB}=6S△DAB=6,则点CCC到ABABAB的距离为( )A.333B.888C.101010D.121212知识点:勾股数章节:图形的性质 / 三角形