题目如图,在△ABC\triangle ABC△ABC中,AB=ACAB=ACAB=AC,△ABC\triangle ABC△ABC的高BHBHBH,CMCMCM交于点PPP.(1)(1)(1)求证:PB=PCPB=PCPB=PC.(2)(2)(2)若PB=5PB=5PB=5,PH=3PH=3PH=3,求ABABAB.知识点:勾股定理章节:图形的性质 / 三角形