题目如表记录了二次函数y=ax2+bx+c(a≠0)y=ax^{2}+bx+c\left(a\neq 0\right)y=ax2+bx+c(a=0)中两个变量xxx与yyy的三组对应值:xxx…\ldots…−2-2−2222888…\ldots…yyy…\ldots…nnn111nnn…\ldots…点P(x1P(x_{1}P(x1,y1)y_{1})y1),Q(x2Q(x_{2}Q(x2,y2)y_{2})y2)在该函数图象上.若当2<x1<x22 \lt x_{1} \lt x_{2}2<x1<x2时,y1<y2<1y_{1} \lt y_{2} \lt 1y1<y2<1,下列四个结论;①a<0a \lt 0a<0;②x1+x2>6x_{1}+x_{2} \gt 6x1+x2>6;③25a+5b+c−1>025a+5b+c-1 \gt 025a+5b+c−1>0;④若记二次函数y=ax2+bx+c(x1<x<8,a≠0)y=ax^{2}+bx+c(x_{1} \lt x \lt 8,a\neq 0)y=ax2+bx+c(x1<x<8,a=0)的图象为图形GGG,存在直线y=ky=ky=k与图形GGG有两个交点,则2<x1<32 \lt x_{1} \lt 32<x1<3.上述结论中,所有正确结论的序号是______.知识点:二次函数的性质I章节:函数 / 二次函数