题目如图,在△ABC\triangle ABC△ABC中,AC=BC=3AC=BC=\sqrt{3}AC=BC=3,ABABAB边上有808080个不同的点.D1D_{1}D1,D2⋯D80(D_{2}\cdots D_{80}(D2⋯D80(异于AAA,BBB两点),记pi=CDi2+ADi×DiB(i=1,2…,80)p_i=CD_i^2+AD_i×D_iB(i=1,2\ldots ,80)pi=CDi2+ADi×DiB(i=1,2…,80),则p1+p2+⋯+p80p_{1}+p_{2}+\cdots +p_{80}p1+p2+⋯+p80的值是( )A.1003100\sqrt{3}1003B.320320320C.1603160\sqrt{3}1603D.240240240知识点:勾股定理章节:图形的性质 / 三角形