题目如图,在平面直角坐标系中,将等腰直角三角形ABOABOABO沿直角边OAOAOA翻折,点BBB落在点CCC处,若点AAA坐标为(3,2)\left(3,2\right)(3,2),则点CCC坐标为( )A.(5,−1)(5,-1)(5,−1)B.(5,−2)(5,-2)(5,−2)C.(6,−1)(6,-1)(6,−1)D.(6,−2)(6,-2)(6,−2)知识点:勾股定理的性质章节:图形的性质 / 三角形