题目(1)(1)(1)解不等式组{3x−2＜x3(x−1)≤5x+2\left\{\begin{array}{c}3x-2＜x\\ 3(x-1)≤5x+2\end{array}\right.{3x−2＜x3(x−1)≤5x+2；(2)(2)(2)解方程组:{x+y=2①2x−y=1②\left\{\begin{array}{l}x+y=2①\\ 2x-y=1②\end{array}\right.{x+y=2①2x−y=1②.知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
