题目综合与探究如图,OOO为△ABC\triangle ABC△ABC的边ABABAB上的一点,以点OOO为圆心,AOAOAO的长为半径作圆,交ABABAB于点DDD,过点AAA作AEAEAE∥BCBCBC,交⊙O\odot O⊙O于点EEE.(1)(1)(1)如图111,连接DEDEDE,若∠B=45∘\angle B=45^{\circ}∠B=45∘,则∠ADE=______.\angle ADE= \_\_\_\_\_\_.∠ADE=______.(2)(2)(2)如图222,连接CDCDCD,交⊙O\odot O⊙O于点FFF,连接AFAFAF,EFEFEF,且∠EFA=∠ACB\angle EFA=\angle ACB∠EFA=∠ACB.①求证:ACACAC为⊙O\odot O⊙O的切线.②若AC=6AC=6AC=6,BC=10BC=10BC=10,AF=EFAF=EFAF=EF,求△BCD\triangle BCD△BCD的面积.知识点:切线的判定章节:图形的性质 / 圆