题目解方程组:(1){x+3y=53x+y=−1(1)\left\{\begin{array}{l}{x+3y=5}\\{3x+y=-1}\end{array}\right.(1){x+3y=53x+y=−1；(2){3(2x−y)+4(x−2y)=432(3x−y)−3(x−y)=0(2)\left\{\begin{array}{l}3(2x-y)+4(x-2y)=43\\ 2(3x-y)-3(x-y)=0\end{array}\right.(2){3(2x−y)+4(x−2y)=432(3x−y)−3(x−y)=0.知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
