题目解二元一次方程组:(1){x=3y,4x+y=13；(1)\left\{\begin{array}{l}x=3y,\\ 4x+y=13；\end{array}\right.(1){x=3y,4x+y=13；(2){4(x−1)+2y=y+8,x3+y2=116.(2)\left\{\begin{array}{l}4(x-1)+2y=y+8,\\ \frac{x}{3}+\frac{y}{2}=\frac{11}{6}.\end{array}\right.(2){4(x−1)+2y=y+8,3x+2y=611.知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
